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x^2+30x-2800=0
a = 1; b = 30; c = -2800;
Δ = b2-4ac
Δ = 302-4·1·(-2800)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12100}=110$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-110}{2*1}=\frac{-140}{2} =-70 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+110}{2*1}=\frac{80}{2} =40 $
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